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Estimating the Amount of Temporary Space for archecker

The archecker utility requires about 15 megabytes of temporary space for a medium-size system (40-50 gigabytes) and 25 megabytes for a large system. This temporary space is stored on the file system in the directory that the AC_STORAGE parameter specifies, not in the dbspaces. The temporary files contain bitmap information about the backup and copies of partition pages, free pages in a chunk, reserved pages, and optionally, free pages in a blobspace and debugging information. The archecker utility must have permissions to the temporary directory.

If the backup is verified successfully, these files are deleted. If the backup fails verification, these files remain. Copy them to another location so that Technical Support can review them.

If your database server contains only dbspaces, use the following formula to estimate the amount of temporary space in kilobytes for the archecker temporary files:

space = (130 KB * number_of_chunks) + (pagesize * number_of_tables) + 
(.05 KB * number_of_logs)
Dynamic Server

If your database server contains blobspaces or sbspaces, use the following formula to estimate the amount of temporary space for the archecker temporary files:

space = (130 KB * number_of_chunks) + (pagesize * number_of_tables) + 
(.05 KB * number_of_logs) + (pagesize * (num_of_blobpages/252))
End of Dynamic Server
number_of_chunks
is the maximum number of chunks that you estimate for the database server.
pagesize
is the system page size in kilobytes.
number_of_tables
is the maximum number of tables that you estimate for the database server.
number_of_logs
is the number of logical logs on the database server.
num_of_blobpages
is the number of blobpages in the blobspaces or the number of sbspaces. (If your database server contains sbspaces, substitute num_of_blobpages with the number of sbspaces.) (IDS only)

For example, you would need 12.9 megabytes of temporary disk space on a 50-gigabyte system with a page size of 2 kilobytes. This system does not contain any blobspaces, as the following statement shows:

13,252 KB = (130 KB * 25 chunks) + (2 KB * 5000 tables) + 
             (.05 KB * 50 logs) + (2 KB * 0)

To convert kilobytes to megabytes, divide the result by 1024:

12.9 MB = 13,252/1024
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